@all those who gave Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80
when it's already given that 5 heads have turned up already then why abut are you adding that probability you all are considering it as finding the probability of finding 6 consecutive heads. since all tosses are independent the answer should be 3/5. the point that 5 heads have turned up already may points that the coin selected is biased in that case pr(6)=1; now the answer depends on the interviewer according to me it should be 3/5 thanks -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
