hey guys thanks got it!!!!!!
On Tue, Aug 9, 2011 at 12:49 PM, sanjay ahuja <sanjayahuja.i...@gmail.com>wrote:
> Int bit3:4 will be read as lower order 4 bits of bit3 and this will be
> treated as int (signed). Thus lower order bit of bit3 which is 2, are
> 0010 which is 2
> try with
> 1) int bit3:2, output will be -2
> 2) unsigned int bit3:2, output will be 2.
>
> I hope it is cleared now
>
> On 8/9/11, Rohit Srivastava <access2ro...@gmail.com> wrote:
> > #include<stdio.h>
> > #include<conio.h>
> >
> > int main()
> > {
> > struct value
> > {
> > int bit1:1;
> > int bit3:4;
> > int bit4:4;
> > }bit={1,2,2};
> > printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
> > getche();
> > return 0;
> > }
> > the above code gives output : -1 2 2
> > any idea why???
> >
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> Sent from my mobile device
>
> Sanjay Ahuja,
> Analyst, Financing Prime Brokerage
> Nomura Securities India Pvt. Ltd
>
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