i dnt get it.. any better explanation..
On Tue, Aug 9, 2011 at 1:13 PM, dinesh bansal <bansal...@gmail.com> wrote:
> On a little-endian machine, bit structure will be represented as:
>
> 0x00 00 00 45
>
> which is bit.bit4 = 0010 (2 in decimal) bit.bit3 = 0010 (2 in decimal)
> bit.bit1 = 1 (1 in decimal)
>
> since bit.bit1 exists at the rightmost position, while displaying data as
> integer, compiler just repeats the same bit to all the remaining positions
> making it 0xffffffff (-1). You can confirm it while setting bit.bit1 to 0
>
> -Dinesh Bansal
>
>
> On Tue, Aug 9, 2011 at 12:24 PM, Rohit Srivastava
> <access2ro...@gmail.com>wrote:
>
>> #include<stdio.h>
>> #include<conio.h>
>>
>> int main()
>> {
>> struct value
>> {
>> int bit1:1;
>> int bit3:4;
>> int bit4:4;
>> }bit={1,2,2};
>> printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
>> getche();
>> return 0;
>> }
>> the above code gives output : -1 2 2
>> any idea why???
>>
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>
>
>
> --
> Dinesh Bansal
> The Law of Win says, "Let's not do it your way or my way; let's do it the
> best way."
>
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