http://en.wikipedia.org/wiki/Birthday_problem

On Aug 17, 5:55 pm, "Romil ......." <vamosro...@gmail.com> wrote:
> Take it as:
> P(atleast 2) = 1-P(no 2 have same b'day) = 1- ((365C50)/50!)
> where C represents the combinations
>
> On Wed, Aug 17, 2011 at 6:14 PM, sukran dhawan <sukrandha...@gmail.com>wrote:
>
>
>
>
>
> > can yo explain it pl?
>
> > On Wed, Aug 17, 2011 at 6:11 PM, Aditya Jain <aditya2...@gmail.com> wrote:
>
> >> Is that exactly 2 or atleast 2?
>
> >> P(atleast 2)=1-P(no 2 people )=1-(364*363*362*.........*317/365^49)
>
> >> On Aug 17, 5:24 pm, priya ramesh <love.for.programm...@gmail.com>
> >> wrote:
> >> > nothing is specified. I guess it's 365
>
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> Romil- Hide quoted text -
>
> - Show quoted text -

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