there is something anamoly about this birthday probability caculation.
Search in google..you may find it.


Regards,
Adi Srikanth.
Mob No 9887233349
Personal Pages: adisrikanth.co.nr


On Wed, Aug 17, 2011 at 6:25 PM, Romil ....... <vamosro...@gmail.com> wrote:

> Take it as:
> P(atleast 2) = 1-P(no 2 have same b'day) = 1- ((365C50)/50!)
> where C represents the combinations
>
> On Wed, Aug 17, 2011 at 6:14 PM, sukran dhawan <sukrandha...@gmail.com>wrote:
>
>> can yo explain it pl?
>>
>>
>> On Wed, Aug 17, 2011 at 6:11 PM, Aditya Jain <aditya2...@gmail.com>wrote:
>>
>>> Is that exactly 2 or atleast 2?
>>>
>>> P(atleast 2)=1-P(no 2 people )=1-(364*363*362*.........*317/365^49)
>>>
>>>
>>>
>>>
>>>
>>> On Aug 17, 5:24 pm, priya ramesh <love.for.programm...@gmail.com>
>>> wrote:
>>> > nothing is specified. I guess it's 365
>>>
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>
>
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