yeah
now if u know then pls tell which is more optimal?

On Fri, Aug 19, 2011 at 11:36 PM, Sanjay Rajpal <srn...@gmail.com> wrote:

> but the logic is same na ?
>
> Sanju
> :)
>
>
>
> On Fri, Aug 19, 2011 at 11:05 AM, sagar pareek <sagarpar...@gmail.com>wrote:
>
>> hmmm ok
>> i found a solution in which index searching is done by 2^i
>> which is more optimal
>> multiplication by 10 or 2 power i ??    i=0,1,2,3.....
>>
>> On Fri, Aug 19, 2011 at 11:30 PM, Sanjay Rajpal <srn...@gmail.com> wrote:
>>
>>> See at each step you are multiplying the index to be compared by 10(say),
>>> this increase is exponential.
>>> Therefore the search is exponential and complexity is log n. Base depends
>>> on the factor by which you are multiplying for the next index to be
>>> compared.
>>>
>>> Sanju
>>> :)
>>>
>>>
>>>
>>> On Fri, Aug 19, 2011 at 10:57 AM, sagar pareek <sagarpar...@gmail.com>wrote:
>>>
>>>> @Sanjay
>>>> yeah its the very basic idea that comes in mind
>>>> but is your index searching log n ?
>>>> i think no !!
>>>> if yes then tell me how?
>>>>
>>>>
>>>> On Fri, Aug 19, 2011 at 11:24 PM, Sanjay Rajpal <srn...@gmail.com>wrote:
>>>>
>>>>> I forgot to mention one thing, at each comparison, store the index at
>>>>> which we searched previously.
>>>>>
>>>>> Sanju
>>>>> :)
>>>>>
>>>>>
>>>>>
>>>>> On Fri, Aug 19, 2011 at 10:53 AM, Sanjay Rajpal <srn...@gmail.com>wrote:
>>>>>
>>>>>> You can do it very easily.
>>>>>>
>>>>>> I assume array is sorted and contains integers.
>>>>>>
>>>>>> Say start at position 1, if value at that index is equal to the value
>>>>>> to be found, return index.
>>>>>> else if value at that index is greater than the value to be found, we
>>>>>> got an interval to search in.
>>>>>> else(value at that index is smaller than the value to be found)
>>>>>>     search at location 10,then 100, then 1000 till you find an
>>>>>> interval.
>>>>>>
>>>>>> Once you find an interval, perform Binary Search on this and get
>>>>>> element in O(log n).
>>>>>>
>>>>>> Got it ?
>>>>>>
>>>>>> Sanju
>>>>>> :)
>>>>>>
>>>>>>
>>>>>>
>>>>>> On Fri, Aug 19, 2011 at 10:48 AM, sagar pareek <sagarpar...@gmail.com
>>>>>> > wrote:
>>>>>>
>>>>>>> HI,
>>>>>>>
>>>>>>> I have encountered a problem :-
>>>>>>>
>>>>>>> You have an array of  *UNKNOWN  *length . And you have to find an
>>>>>>> element in  O(log(n)) time without using any extra space.
>>>>>>>
>>>>>>> --
>>>>>>> **Regards
>>>>>>> SAGAR PAREEK
>>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>>> NIT ALLAHABAD
>>>>>>>
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>>>> SAGAR PAREEK
>>>> COMPUTER SCIENCE AND ENGINEERING
>>>> NIT ALLAHABAD
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>> COMPUTER SCIENCE AND ENGINEERING
>> NIT ALLAHABAD
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-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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