Multiplication by 10 or 2^i , it depends.

Multiplication by 10 will be faster, I think.

Sanju
:)



On Fri, Aug 19, 2011 at 11:05 AM, sagar pareek <sagarpar...@gmail.com>wrote:

> hmmm ok
> i found a solution in which index searching is done by 2^i
> which is more optimal
> multiplication by 10 or 2 power i ??    i=0,1,2,3.....
>
> On Fri, Aug 19, 2011 at 11:30 PM, Sanjay Rajpal <srn...@gmail.com> wrote:
>
>> See at each step you are multiplying the index to be compared by 10(say),
>> this increase is exponential.
>> Therefore the search is exponential and complexity is log n. Base depends
>> on the factor by which you are multiplying for the next index to be
>> compared.
>>
>> Sanju
>> :)
>>
>>
>>
>> On Fri, Aug 19, 2011 at 10:57 AM, sagar pareek <sagarpar...@gmail.com>wrote:
>>
>>> @Sanjay
>>> yeah its the very basic idea that comes in mind
>>> but is your index searching log n ?
>>> i think no !!
>>> if yes then tell me how?
>>>
>>>
>>> On Fri, Aug 19, 2011 at 11:24 PM, Sanjay Rajpal <srn...@gmail.com>wrote:
>>>
>>>> I forgot to mention one thing, at each comparison, store the index at
>>>> which we searched previously.
>>>>
>>>> Sanju
>>>> :)
>>>>
>>>>
>>>>
>>>> On Fri, Aug 19, 2011 at 10:53 AM, Sanjay Rajpal <srn...@gmail.com>wrote:
>>>>
>>>>> You can do it very easily.
>>>>>
>>>>> I assume array is sorted and contains integers.
>>>>>
>>>>> Say start at position 1, if value at that index is equal to the value
>>>>> to be found, return index.
>>>>> else if value at that index is greater than the value to be found, we
>>>>> got an interval to search in.
>>>>> else(value at that index is smaller than the value to be found)
>>>>>     search at location 10,then 100, then 1000 till you find an
>>>>> interval.
>>>>>
>>>>> Once you find an interval, perform Binary Search on this and get
>>>>> element in O(log n).
>>>>>
>>>>> Got it ?
>>>>>
>>>>> Sanju
>>>>> :)
>>>>>
>>>>>
>>>>>
>>>>> On Fri, Aug 19, 2011 at 10:48 AM, sagar pareek 
>>>>> <sagarpar...@gmail.com>wrote:
>>>>>
>>>>>> HI,
>>>>>>
>>>>>> I have encountered a problem :-
>>>>>>
>>>>>> You have an array of  *UNKNOWN  *length . And you have to find an
>>>>>> element in  O(log(n)) time without using any extra space.
>>>>>>
>>>>>> --
>>>>>> **Regards
>>>>>> SAGAR PAREEK
>>>>>> COMPUTER SCIENCE AND ENGINEERING
>>>>>> NIT ALLAHABAD
>>>>>>
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>>>
>>>
>>>
>>> --
>>> **Regards
>>> SAGAR PAREEK
>>> COMPUTER SCIENCE AND ENGINEERING
>>> NIT ALLAHABAD
>>>
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>
>
>
> --
> **Regards
> SAGAR PAREEK
> COMPUTER SCIENCE AND ENGINEERING
> NIT ALLAHABAD
>
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