@Sivaviknesh: The smallest values of x and y are 1. The largest value
of y is (60 - 3) / 4 = 14. Solve for x: x = (60 - 4y) / 3. Since x is
an integer, 60 - 4y must be a multiple of 3. Since 60 - 3y is a
multiple of 3, (60 - 4y) - (60 - 3y) = y must be a multiple of 3.
Thus, y = 3, 6, 9, 12. Then you can solve for the corresponding values
of x.

Dave

On Aug 28, 7:46 am, sivaviknesh s <sivavikne...@gmail.com> wrote:
> *Find the number of solutions for 3x+4y=60, if x and y are positive
> integers.*
>
> Is there any standard method for solving these type of ques ..or only trial
> and error ???
>
> --
> Regards,
> $iva

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