3x+4y = 60 can be expressed as 15 -y = 3x+3y -45 i.e, 15-y = 3(x+y-15) which implies tht for every value of x,y in the above eq 15-y is divisible by 3
On Sun, Aug 28, 2011 at 10:03 PM, Dave <dave_and_da...@juno.com> wrote: > @Harhsit: Normally, 0 is not considered positive. > > Dave > > On Aug 28, 10:45 am, harshit sethi <hshoneyma...@gmail.com> wrote: > > sorry 6 solutions y=15,12,9,6,3,0 > > and x=0,4,8,12,16,20 respectively > > > > On 8/28/11, harshit sethi <hshoneyma...@gmail.com> wrote: > > > > > > > > > maximum value of y satisfying this is y=15 and for that x=0; > > > > > now decrease y by 3 and increase x by 4 ,you will have x and y > > > satisfying the equation. > > > > > keep on doing this till you reach minimum value of y i.e 0 > > > > > this you can do 5 times decreasing y=15 by 3 every time > > > > > so there will be 5 solutions . > > > > > On 8/28/11, Piyush Grover <piyush4u.iit...@gmail.com> wrote: > > >> 3x+4y = 60 > > >> it's a straight line equation whose x intercept is 20 and y intercept > is > > >> 15. > > >> Draw it in first quadrant > > >> (as x, y are positive integers) > > >> now x = (60 - 4y)/3 = 4(15-y)/3 > > >> now for y = 1, 2...15 you need to check whether (15-y) is divisible by > 3 > > >> or > > >> not. It's simple y = 3, 6, 9, 12 > > > > >> -Piyush > > > > >> On Sun, Aug 28, 2011 at 6:38 PM, Dave <dave_and_da...@juno.com> > wrote: > > > > >>> @Sivaviknesh: The smallest values of x and y are 1. The largest value > > >>> of y is (60 - 3) / 4 = 14. Solve for x: x = (60 - 4y) / 3. Since x is > > >>> an integer, 60 - 4y must be a multiple of 3. Since 60 - 3y is a > > >>> multiple of 3, (60 - 4y) - (60 - 3y) = y must be a multiple of 3. > > >>> Thus, y = 3, 6, 9, 12. Then you can solve for the corresponding > values > > >>> of x. > > > > >>> Dave > > > > >>> On Aug 28, 7:46 am, sivaviknesh s <sivavikne...@gmail.com> wrote: > > >>> > *Find the number of solutions for 3x+4y=60, if x and y are positive > > >>> > integers.* > > > > >>> > Is there any standard method for solving these type of ques ..or > only > > >>> trial > > >>> > and error ??? > > > > >>> > -- > > >>> > Regards, > > >>> > $iva > > > > >>> -- > > >>> You received this message because you are subscribed to the Google > > >>> Groups > > >>> "Algorithm Geeks" group. > > >>> To post to this group, send email to algogeeks@googlegroups.com. > > >>> To unsubscribe from this group, send email to > > >>> algogeeks+unsubscr...@googlegroups.com. > > >>> For more options, visit this group at > > >>>http://groups.google.com/group/algogeeks?hl=en. > > > > >> -- > > >> You received this message because you are subscribed to the Google > Groups > > >> "Algorithm Geeks" group. > > >> To post to this group, send email to algogeeks@googlegroups.com. > > >> To unsubscribe from this group, send email to > > >> algogeeks+unsubscr...@googlegroups.com. > > >> For more options, visit this group at > > >>http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - > > > > - Show quoted text - > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Rishabbh A Dua -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
