3x+4y = 60
it's a straight line equation whose x intercept is 20 and y intercept is 15.
Draw it in first quadrant
(as x, y are positive integers)
now x = (60 - 4y)/3 = 4(15-y)/3
now for y = 1, 2...15 you need to check whether (15-y) is divisible by 3 or
not. It's simple y = 3, 6, 9, 12

-Piyush

On Sun, Aug 28, 2011 at 6:38 PM, Dave <dave_and_da...@juno.com> wrote:

> @Sivaviknesh: The smallest values of x and y are 1. The largest value
> of y is (60 - 3) / 4 = 14. Solve for x: x = (60 - 4y) / 3. Since x is
> an integer, 60 - 4y must be a multiple of 3. Since 60 - 3y is a
> multiple of 3, (60 - 4y) - (60 - 3y) = y must be a multiple of 3.
> Thus, y = 3, 6, 9, 12. Then you can solve for the corresponding values
> of x.
>
> Dave
>
> On Aug 28, 7:46 am, sivaviknesh s <sivavikne...@gmail.com> wrote:
> > *Find the number of solutions for 3x+4y=60, if x and y are positive
> > integers.*
> >
> > Is there any standard method for solving these type of ques ..or only
> trial
> > and error ???
> >
> > --
> > Regards,
> > $iva
>
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