p is a pointer to an array of 4 integers. So when you do (int(*)
[col])malloc(row*sizeof(*p)) total of 48 bytes is allocated as
sizeof(*p) is 12 bytes.
On Sep 3, 4:14 pm, rohit <rajuljain...@gmail.com> wrote:
> how many bytes are allocated by following code?
>
> #include<alloc.h>
> #define col 4
> #define row 3
>
> int main()
> {
> int(*p)[col];
> p=(int(*)[col])malloc(row*sizeof(*p));
>
> return 0;
>
> }
>
> please explain answer?
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