no. of rows is 3
size of (*p) is 12
then how can 48 be the no. of bytes ??
On Sat, Sep 3, 2011 at 8:32 AM, Deepak Garg <deepakgarg...@gmail.com> wrote:
> +1
>
>
> On Sat, Sep 3, 2011 at 8:57 PM, Ankuj Gupta <ankuj2...@gmail.com> wrote:
>
>> p is a pointer to an array of 4 integers. So when you do (int(*)
>> [col])malloc(row*sizeof(*p)) total of 48 bytes is allocated as
>> sizeof(*p) is 12 bytes.
>>
>> On Sep 3, 4:14 pm, rohit <rajuljain...@gmail.com> wrote:
>> > how many bytes are allocated by following code?
>> >
>> > #include<alloc.h>
>> > #define col 4
>> > #define row 3
>> >
>> > int main()
>> > {
>> > int(*p)[col];
>> > p=(int(*)[col])malloc(row*sizeof(*p));
>> >
>> > return 0;
>> >
>> > }
>> >
>> > please explain answer?
>>
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>
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Malaviya National Institute of Technology
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