int(*p)[col];
Here, p is a pointer to an array of 4 integers.
Size of *p is 4X4 = 16.
p=(int(*)[col])malloc(row*sizeof(*p));
here clearly 3X 16 = 48 bytes of memory is being allocated.
On Sat, Sep 3, 2011 at 9:14 PM, piyush agarwal <pshagl...@gmail.com> wrote:
> no. of rows is 3
> size of (*p) is 12
> then how can 48 be the no. of bytes ??
>
> On Sat, Sep 3, 2011 at 8:32 AM, Deepak Garg <deepakgarg...@gmail.com>wrote:
>
>> +1
>>
>>
>> On Sat, Sep 3, 2011 at 8:57 PM, Ankuj Gupta <ankuj2...@gmail.com> wrote:
>>
>>> p is a pointer to an array of 4 integers. So when you do (int(*)
>>> [col])malloc(row*sizeof(*p)) total of 48 bytes is allocated as
>>> sizeof(*p) is 12 bytes.
>>>
>>> On Sep 3, 4:14 pm, rohit <rajuljain...@gmail.com> wrote:
>>> > how many bytes are allocated by following code?
>>> >
>>> > #include<alloc.h>
>>> > #define col 4
>>> > #define row 3
>>> >
>>> > int main()
>>> > {
>>> > int(*p)[col];
>>> > p=(int(*)[col])malloc(row*sizeof(*p));
>>> >
>>> > return 0;
>>> >
>>> > }
>>> >
>>> > please explain answer?
>>>
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>
>
> --
> Piyush Agarwal
> Final Year Undergraduate
> Department of Computer Engineering
> Malaviya National Institute of Technology
> Jaipur
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