i=0;
char *str;
while(a[i]!=NULL)
{
   j=0;

   while(j!=i)
   {
      for(k=j;k<=i;k++)
      {
         l=0;
         str[l]=a[j];
      }
      if(Dictionary.findword(str))
      printf(str);
      j++;
   }
}


...
On Mon, Sep 19, 2011 at 8:20 PM, Sangeeta <sangeeta15...@gmail.com> wrote:

> given an array of characters without spaces and a dictionary.All valid
> dictionary words must be found and printed.
> i/p : BANKERKCATXYWOMAN.
> o/p: BANK
> BANKER
> CAT
> WOMAN
> MAN
> (the only function you could use for dictionary is
> dictionary.findword(char *str) which returns a Boolean value).
> Eg. Dictionary.findword(“bank”) =>true
> Dictionary.findword(“hj”) =>false
>
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