Re: [algogeeks] All valid dictionary words must be found and printed.

[Yogesh Yadav]

// there were some mistakes...

so...

i=0;
char *str;
while(a[i]!=NULL)
{
   j=0;

   while(j!=i)
   {
      l=0;
      for(k=j;k<=i;k++)
      {

         str[l]=a[j];
         l++
      }
      if(Dictionary.findword(str))
      printf(str);
      j++;
   }
}
On Mon, Sep 19, 2011 at 8:44 PM, Yogesh Yadav <medu...@gmail.com> wrote:

> i=0;
> char *str;
> while(a[i]!=NULL)
> {
>    j=0;
>
>    while(j!=i)
>    {
>       for(k=j;k<=i;k++)
>       {
>          l=0;
>          str[l]=a[j];
>       }
>       if(Dictionary.findword(str))
>       printf(str);
>       j++;
>    }
> }
>
>
> ...
>
> On Mon, Sep 19, 2011 at 8:20 PM, Sangeeta <sangeeta15...@gmail.com> wrote:
>
>> given an array of characters without spaces and a dictionary.All valid
>> dictionary words must be found and printed.
>> i/p : BANKERKCATXYWOMAN.
>> o/p: BANK
>> BANKER
>> CAT
>> WOMAN
>> MAN
>> (the only function you could use for dictionary is
>> dictionary.findword(char *str) which returns a Boolean value).
>> Eg. Dictionary.findword(“bank”) =>true
>> Dictionary.findword(“hj”) =>false
>>
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>>
>

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