construct a trie.. then a simple recursion on the trie ll do ... :) any
standard tutorial on tries ll help u build one ...
then the recursion part should look something like this,
start scanning from root of tire.
if(end of word is found)
{
take is as a word, start searching from root of a trie + consider this as
a prefix and proceed from the current state itself
}
else
proceed to next state
On Mon, Sep 19, 2011 at 8:20 PM, Sangeeta <sangeeta15...@gmail.com> wrote:
> given an array of characters without spaces and a dictionary.All valid
> dictionary words must be found and printed.
> i/p : BANKERKCATXYWOMAN.
> o/p: BANK
> BANKER
> CAT
> WOMAN
> MAN
> (the only function you could use for dictionary is
> dictionary.findword(char *str) which returns a Boolean value).
> Eg. Dictionary.findword(“bank”) =>true
> Dictionary.findword(“hj”) =>false
>
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