n=1 n=2 n=3 n=4
0 10 10! (10!)!
1 9 9! (9!)!
2 8 8!
3 7 7!
4 6 6!
5 5 5!
6 4 4!
7 3 3!
8 2 2!
9 1 1!
sum 10 55 220 and so on....
On Sun, Sep 25, 2011 at 11:46 AM, Sanjay Rajpal <srn...@gmail.com> wrote:
> Can you plz tell the answer for
> for 3 answer=?
> nd for 4 answer=?
> Sanju
> :)
>
>
>
> On Sat, Sep 24, 2011 at 10:39 PM, Dheeraj Sharma <
> dheerajsharma1...@gmail.com> wrote:
>
>> can u plz be more..clear ..with wat the input will consist of..
>> wat does this mean
>> "for 2 answer=55"
>> does that mean..that how many non decreasing digits can be formed by 2
>> digit num
>>
>>
>> On Sun, Sep 25, 2011 at 1:08 AM, shady <sinv...@gmail.com> wrote:
>>
>>> A number is said to be made up of non-decreasing digits if all the digits
>>> to the left of any digit is less than or equal to that digit. for eg. 1122,
>>> 234, 2
>>>
>>> 0000, 0011 is a possible 4 digit non decreasing number
>>>
>>> so given a number n, how many n digit numbers exist ?
>>>
>>> for 2 answer = 55
>>>
>>> Can someone post complexity and their approach....
>>>
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>>
>>
>>
>> --
>> *Dheeraj Sharma*
>> Comp Engg.
>> NIT Kurukshetra
>>
>>
>>
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