mistake in last post...it was not factorial....sum upto n i.e =n(n+1)/2

i.e 10! is wrong ...it will be 10(10+1)/2


....
On Sun, Sep 25, 2011 at 12:14 PM, Yogesh Yadav <medu...@gmail.com> wrote:

>        n=1     n=2       n=3       n=4
>          0        10        10!        (10!)!
>          1          9          9!         (9!)!
>          2          8          8!
>          3          7          7!
>          4          6          6!
>          5          5          5!
>          6          4          4!
>          7          3          3!
>          8          2          2!
>          9          1          1!
> sum  10         55        220      and so on....
>
>
>
> On Sun, Sep 25, 2011 at 11:46 AM, Sanjay Rajpal <srn...@gmail.com> wrote:
>
>> Can you plz tell the answer for
>> for 3 answer=?
>> nd for 4 answer=?
>> Sanju
>> :)
>>
>>
>>
>> On Sat, Sep 24, 2011 at 10:39 PM, Dheeraj Sharma <
>> dheerajsharma1...@gmail.com> wrote:
>>
>>> can u plz be more..clear ..with wat the input will consist of..
>>> wat does this mean
>>> "for 2 answer=55"
>>> does that mean..that how many non decreasing digits can be formed by 2
>>> digit num
>>>
>>>
>>> On Sun, Sep 25, 2011 at 1:08 AM, shady <sinv...@gmail.com> wrote:
>>>
>>>> A number is said to be made up of non-decreasing digits if all the
>>>> digits to the left of any digit is less than or equal to that digit. for 
>>>> eg.
>>>> 1122, 234, 2
>>>>
>>>> 0000, 0011 is a possible 4 digit non decreasing number
>>>>
>>>> so given a number n, how many n digit numbers exist ?
>>>>
>>>> for 2 answer = 55
>>>>
>>>> Can someone post complexity and their approach....
>>>>
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>>>
>>>
>>>
>>> --
>>> *Dheeraj Sharma*
>>> Comp Engg.
>>> NIT Kurukshetra
>>>
>>>
>>>
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>
>

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