yeah exactly..yogesh..i was confused with factorial

On Sun, Sep 25, 2011 at 12:21 PM, Yogesh Yadav <medu...@gmail.com> wrote:

> mistake in last post...it was not factorial....sum upto n i.e =n(n+1)/2
>
> i.e 10! is wrong ...it will be 10(10+1)/2
>
>
> ....
> On Sun, Sep 25, 2011 at 12:14 PM, Yogesh Yadav <medu...@gmail.com> wrote:
>
>>        n=1     n=2       n=3       n=4
>>          0        10        10!        (10!)!
>>          1          9          9!         (9!)!
>>          2          8          8!
>>          3          7          7!
>>          4          6          6!
>>          5          5          5!
>>          6          4          4!
>>          7          3          3!
>>          8          2          2!
>>          9          1          1!
>> sum  10         55        220      and so on....
>>
>>
>>
>> On Sun, Sep 25, 2011 at 11:46 AM, Sanjay Rajpal <srn...@gmail.com> wrote:
>>
>>> Can you plz tell the answer for
>>> for 3 answer=?
>>> nd for 4 answer=?
>>> Sanju
>>> :)
>>>
>>>
>>>
>>> On Sat, Sep 24, 2011 at 10:39 PM, Dheeraj Sharma <
>>> dheerajsharma1...@gmail.com> wrote:
>>>
>>>> can u plz be more..clear ..with wat the input will consist of..
>>>> wat does this mean
>>>> "for 2 answer=55"
>>>> does that mean..that how many non decreasing digits can be formed by 2
>>>> digit num
>>>>
>>>>
>>>> On Sun, Sep 25, 2011 at 1:08 AM, shady <sinv...@gmail.com> wrote:
>>>>
>>>>> A number is said to be made up of non-decreasing digits if all the
>>>>> digits to the left of any digit is less than or equal to that digit. for 
>>>>> eg.
>>>>> 1122, 234, 2
>>>>>
>>>>> 0000, 0011 is a possible 4 digit non decreasing number
>>>>>
>>>>> so given a number n, how many n digit numbers exist ?
>>>>>
>>>>> for 2 answer = 55
>>>>>
>>>>> Can someone post complexity and their approach....
>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> *Dheeraj Sharma*
>>>> Comp Engg.
>>>> NIT Kurukshetra
>>>>
>>>>
>>>>
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>>
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-- 
*Dheeraj Sharma*
Comp Engg.
NIT Kurukshetra

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