@Wladimir, yeah I have heard about that. Another way of populating primitive
pythagoreans is, for any natural number m > 1  (m^2 - 1, 2m, m^2 + 1) forms
a pythagorean triplet. This is useful in populating pythagorean tiplets but
here the problem is to search such triplets from a given int array.

@ rahul, Hash of z^2 - x^2 for each pair of z,x itself will of the size
n*(n-1). I am not sure how it will work in O(n) time then.

Thanks,
- Ravindra

On Fri, Oct 14, 2011 at 12:25 AM, Ankur Garg <ankurga...@gmail.com> wrote:

> @rahul...How do u choose z and x for computing z^2 -x^2 ?
>
> On Thu, Oct 13, 2011 at 11:34 PM, rahul <rahul...@gmail.com> wrote:
>
>> You can create a hash with sqrt(z2-x2). This will make it o(n). The
>> interviewer just made it lil tricky. That's all
>>
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