This appears to be n^(3/2) complexity, looking at one of the solutions in
http://stackoverflow.com/questions/575117/pythagorean-triplets
assuming elements as sorted. (x cannot be greater than sqrt(2z) as x2+y2 =
z2 --> for the worst value of y2 --> 2x^2 = z2
MaxX = ( 2 * N - 1 ) ** 0.5
for x in 3..MaxX {
y = x+1
z = y+1
m = x*x + y*y
k = z * z
while z <= N {
while k < m {
z = z + 1
k = k + (2*z) - 1
}
if k == m and z <= N then {
// use x, y, z
}
y = y + 1
m = m + (2 * y) - 1
}
}
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