it wont work

even this wont

function(char a[])
function (char *)
coz the two forms are interchangeable

On Sun, Nov 20, 2011 at 10:12 PM, saurabh singh <saurab...@gmail.com> wrote:

> wont work......Thre is no way compilers gonna guess which function to
> call.The const qualifier only guarantees that the value at the address wont
> be altered inside the function.That has nothing to do with calling,
>
>
> On Sun, Nov 20, 2011 at 9:50 PM, rahul vatsa <vatsa.ra...@gmail.com>wrote:
>
>> yes, it will work.
>>
>>
>> On Sun, Nov 20, 2011 at 9:12 PM, Akash Coder 
>> <akash.coder.g...@gmail.com>wrote:
>>
>>> no it wont work ... const is not a datatype. its  a qualifier
>>>
>>>
>>> On Sun, Nov 20, 2011 at 7:49 PM, rahul sharma 
>>> <rahul23111...@gmail.com>wrote:
>>>
>>>> void fun(char *)
>>>> void fun(const char *)
>>>>
>>>>
>>>>
>>>> is this overloading works or these are same type of arguments??????
>>>>
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>
>
>
> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD
>
>
>
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