Run this one:
#include<stdio.h>
void fun(const char *p)
{
printf("const\n");
}
void fun(char *P)
{
printf("simple\n");
}
int main(void)
{
char str[] = "funcheck";
//const char str1[] =
"constcheck";
fun(str);
fun(str);
}
On Tue, Nov 22, 2011 at 7:13 PM, MJ <mayurdj...@gmail.com> wrote:
> Hi
> This type of function overloading works in c .
> Execute following code and it will call function fun as per the
> function parameter
>
> code snip-in
> ---------------------
> #include<stdio.h>
> void fun(const char *p)
> {
> printf("funsfsdafsf1\n");
> }
> void fun(char *P)
> {
> printf("fun2\n");
> }
> void main()
> {
> char str[] = "funcheck";
> const char str1[] = "constcheck";
> fun(str);
> fun(str1);
> }
> ---------------------
>
> output
> ------------
> fun2
> funsfsdafsf1
> ----------------
>
> Mayur
>
>
> On Nov 21, 6:30 pm, Anil Arya <anilarya...@gmail.com> wrote:
> > dude....compile using g++
> >
> > On 11/21/11, atul anand <atul.87fri...@gmail.com> wrote:
> >
> >
> >
> >
> >
> >
> >
> >
> >
> > > this is what i am getting after executing code meintion in the above
> link.
> >
> > > (using gcc compiler )
> >
> > > temp.c:12: error: conflicting types for 'fun'
> > > temp.c:7: error: previous definition of 'fun' was here
> >
> > > On Mon, Nov 21, 2011 at 3:09 PM, UTKARSH SRIVASTAV
> > > <usrivastav...@gmail.com>wrote:
> >
> > >>http://www.ideone.com/JQFNh
> > >> CHECK THE OUTPUT THERE IS NO AMBIGUITY BUT PLEASE EXPLAIN THE RESULTS
> >
> > >> On Sun, Nov 20, 2011 at 11:00 PM, Akash Coder
> > >> <akash.coder.g...@gmail.com>wrote:
> >
> > >>> it wont work
> >
> > >>> even this wont
> >
> > >>> function(char a[])
> > >>> function (char *)
> > >>> coz the two forms are interchangeable
> >
> > >>> On Sun, Nov 20, 2011 at 10:12 PM, saurabh singh
> > >>> <saurab...@gmail.com>wrote:
> >
> > >>>> wont work......Thre is no way compilers gonna guess which function
> to
> > >>>> call.The const qualifier only guarantees that the value at the
> address
> > >>>> wont
> > >>>> be altered inside the function.That has nothing to do with calling,
> >
> > >>>> On Sun, Nov 20, 2011 at 9:50 PM, rahul vatsa
> > >>>> <vatsa.ra...@gmail.com>wrote:
> >
> > >>>>> yes, it will work.
> >
> > >>>>> On Sun, Nov 20, 2011 at 9:12 PM, Akash Coder <
> > >>>>> akash.coder.g...@gmail.com> wrote:
> >
> > >>>>>> no it wont work ... const is not a datatype. its a qualifier
> >
> > >>>>>> On Sun, Nov 20, 2011 at 7:49 PM, rahul sharma <
> rahul23111...@gmail.com
> > >>>>>> > wrote:
> >
> > >>>>>>> void fun(char *)
> > >>>>>>> void fun(const char *)
> >
> > >>>>>>> is this overloading works or these are same type of
> arguments??????
> >
> > >>>>>>> --
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> >
> > >>>>>> --
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> >
> > >>>> --
> > >>>> Saurabh Singh
> > >>>> B.Tech (Computer Science)
> > >>>> MNNIT ALLAHABAD
> >
> > >>>> --
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> >
> > >>> --
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> >
> > >> --
> > >> *UTKARSH SRIVASTAV
> > >> CSE-3
> > >> B-Tech 3rd Year
> > >> @MNNIT ALLAHABAD*
> >
> > >> --
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> > > --
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> >
> > --
> > *Anil Arya,
> > Computer Science *
> > *Motilal Nehru National Institute of Technology,Allahabad .
> > *
>
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