dude....compile using g++

On 11/21/11, atul anand <atul.87fri...@gmail.com> wrote:
> this is what i am getting after executing code meintion in the above link.
>
> (using gcc compiler )
>
> temp.c:12: error: conflicting types for 'fun'
> temp.c:7: error: previous definition of 'fun' was here
>
>
> On Mon, Nov 21, 2011 at 3:09 PM, UTKARSH SRIVASTAV
> <usrivastav...@gmail.com>wrote:
>
>> http://www.ideone.com/JQFNh
>> CHECK THE OUTPUT THERE IS NO AMBIGUITY BUT PLEASE EXPLAIN THE RESULTS
>>
>>
>> On Sun, Nov 20, 2011 at 11:00 PM, Akash Coder
>> <akash.coder.g...@gmail.com>wrote:
>>
>>> it wont work
>>>
>>> even this wont
>>>
>>> function(char a[])
>>> function (char *)
>>> coz the two forms are interchangeable
>>>
>>>
>>> On Sun, Nov 20, 2011 at 10:12 PM, saurabh singh
>>> <saurab...@gmail.com>wrote:
>>>
>>>> wont work......Thre is no way compilers gonna guess which function to
>>>> call.The const qualifier only guarantees that the value at the address
>>>> wont
>>>> be altered inside the function.That has nothing to do with calling,
>>>>
>>>>
>>>> On Sun, Nov 20, 2011 at 9:50 PM, rahul vatsa
>>>> <vatsa.ra...@gmail.com>wrote:
>>>>
>>>>> yes, it will work.
>>>>>
>>>>>
>>>>> On Sun, Nov 20, 2011 at 9:12 PM, Akash Coder <
>>>>> akash.coder.g...@gmail.com> wrote:
>>>>>
>>>>>> no it wont work ... const is not a datatype. its  a qualifier
>>>>>>
>>>>>>
>>>>>> On Sun, Nov 20, 2011 at 7:49 PM, rahul sharma <rahul23111...@gmail.com
>>>>>> > wrote:
>>>>>>
>>>>>>> void fun(char *)
>>>>>>> void fun(const char *)
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> is this overloading works or these are same type of arguments??????
>>>>>>>
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>>>>
>>>>
>>>> --
>>>> Saurabh Singh
>>>> B.Tech (Computer Science)
>>>> MNNIT ALLAHABAD
>>>>
>>>>
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>>
>>
>>
>> --
>> *UTKARSH SRIVASTAV
>> CSE-3
>> B-Tech 3rd Year
>> @MNNIT ALLAHABAD*
>>
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>
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>


-- 
*Anil  Arya,
Computer Science *
*Motilal Nehru National Institute of Technology,Allahabad .
*

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