If you maintain the parent, it'll be a simple problem.
Just go to the two nodes and then trace their parents till you reach the
common node.
On Tue, Nov 22, 2011 at 1:59 PM, anshu mishra <anshumishra6...@gmail.com>wrote:
> first try to understand the sol then comment. it is for binary tree not
> for BST.
>
> On Mon, Nov 21, 2011 at 10:25 PM, Piyush Grover <piyush4u.iit...@gmail.com
> > wrote:
>
>> For BST it would be rather simpler. find the first node which lies in
>> between the two.
>>
>> On Wed, Nov 16, 2011 at 1:44 PM, anshu mishra
>> <anshumishra6...@gmail.com>wrote:
>>
>>> Node *LCA(node *root, node *e1, node *e2, int &x)
>>>
>>> {
>>>
>>> Node *temp =NULL;
>>>
>>> Int y = 0;
>>>
>>> If (root->left) temp = LCA(root->left, e1, e2, y);
>>>
>>> x+=y;
>>>
>>> if (temp) return temp;
>>>
>>> if (x==2) return node;
>>>
>>> y = 0;
>>>
>>> If (root->right) temp = LCA(root->right, e1, e2, y);
>>>
>>> x+=y;
>>>
>>> if (temp) return temp;
>>>
>>> if (x==2) return node;
>>>
>>> If (root == e1 || root == e2) x++;
>>>
>>> Return null;
>>>
>>> }
>>>
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>
>
>
> --
> Anshuman Mishra | Software Development Engineer | Amazon
>
>
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Regards
*Abhishek*
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