@anshu
I was just replying to the earlier comments not to ur post.
On Tue, Nov 22, 2011 at 2:23 PM, abhishek kumar <abhi5...@gmail.com> wrote:
> If you maintain the parent, it'll be a simple problem.
> Just go to the two nodes and then trace their parents till you reach the
> common node.
>
>
> On Tue, Nov 22, 2011 at 1:59 PM, anshu mishra
> <anshumishra6...@gmail.com>wrote:
>
>> first try to understand the sol then comment. it is for binary tree not
>> for BST.
>>
>> On Mon, Nov 21, 2011 at 10:25 PM, Piyush Grover <
>> piyush4u.iit...@gmail.com> wrote:
>>
>>> For BST it would be rather simpler. find the first node which lies in
>>> between the two.
>>>
>>> On Wed, Nov 16, 2011 at 1:44 PM, anshu mishra <anshumishra6...@gmail.com
>>> > wrote:
>>>
>>>> Node *LCA(node *root, node *e1, node *e2, int &x)
>>>>
>>>> {
>>>>
>>>> Node *temp =NULL;
>>>>
>>>> Int y = 0;
>>>>
>>>> If (root->left) temp = LCA(root->left, e1, e2, y);
>>>>
>>>> x+=y;
>>>>
>>>> if (temp) return temp;
>>>>
>>>> if (x==2) return node;
>>>>
>>>> y = 0;
>>>>
>>>> If (root->right) temp = LCA(root->right, e1, e2, y);
>>>>
>>>> x+=y;
>>>>
>>>> if (temp) return temp;
>>>>
>>>> if (x==2) return node;
>>>>
>>>> If (root == e1 || root == e2) x++;
>>>>
>>>> Return null;
>>>>
>>>> }
>>>>
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>>>
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>>
>>
>>
>> --
>> Anshuman Mishra | Software Development Engineer | Amazon
>>
>>
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>
>
>
> --
> Regards
> *Abhishek*
>
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