@atul
TC can be bound to O(nlgn) using any balanced tree ie: AVL tree, RB tree as
already mentioned in her last post

On Mon, Mar 12, 2012 at 10:44 PM, atul anand <atul.87fri...@gmail.com>wrote:

> @payal:
> TC will not alwayz be O(nlogn) bcozz we are not sure if the tree formed is
> balanced.
> so worst would be O(n^2)
>
>
> On Mon, Mar 12, 2012 at 9:16 PM, payal gupta <gpt.pa...@gmail.com> wrote:
>
>> @atul...
>> if its the sum of the elements to the left of a[i] which are smaller the
>> my approach works w/o any flaw....
>> here's the working code for it....http://ideone.com/CH7VW
>> if its the sum of all elements lesser than the element a[i] then this
>> algo is surely wrong
>> n we then have to proceed by the avl trees or some height balanced tree n
>> the algo would be of TC-O(nlogn)
>> btw nyc catch thnx...
>>
>> Regards,
>> PAYAL GUPTA
>>
>>
>>
>> On Mon, Mar 12, 2012 at 5:19 PM, Piyush Kapoor <pkjee2...@gmail.com>wrote:
>>
>>> 1)First map the array numbers into the position in which they would be,
>>> if they are sorted,for example
>>> {30,50,10,60,77,88} ---> {2,3,1,4,5,6}
>>> 2)Now for each number ,find the cumulative frequency of index ( = the
>>> corresponding number in the map - 1).
>>> 3)Output the cumulative frequency and increase the frequency  at the
>>> position (=the corresponding number in the map) by the number itself.
>>> Example
>>> {3,5,1,6,7,8}  Map of which would be {2,3,1,4,5,6}
>>> Process the numbers now,
>>> 1)3 comes ,find the cumulative frequency at index 1 ( = 2-1) which is 0.
>>> so output 0
>>>    Increase the frequency at index 2 to the number 3.
>>> 2)5 comes,find the CF at index 2( = 3-1) which is equal to 3 .output 3.
>>>    Increase the frequency at index 3 to the number 5.
>>> 3)1 comes,CF at index 0 (=1-1) = 0 so output 0.increase the F at
>>> position 1 by 1.
>>> Similarly for others.
>>>
>>>
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-- 
Sunny Aggrawal
B.Tech. V year,CSI
Indian Institute Of Technology,Roorkee

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