yes It's valid, cuz  it doesn't have any repeated substring next together

On Tue, Jun 5, 2012 at 7:08 PM, Lomash Goyal <lomesh.go...@gmail.com> wrote:

> is geke is a invalid strng?
>
>
> On Tue, Jun 5, 2012 at 12:17 PM, Hassan Monfared <hmonfa...@gmail.com>wrote:
>
>> Ashish:
>>
>> the algorithm passes over string and check if there is any substring with
>> len=1 is repeated or not. if not, tries for substring with len 2,... and so
>> on.
>> max length of substring which can be repeated can be at most  N/2.
>>
>>
>> Regards,
>>
>>
>> On Tue, Jun 5, 2012 at 10:48 AM, Ashish Goel <ashg...@gmail.com> wrote:
>>
>>> The problem suggests that a character can't be more than once present
>>> and thereby it can be done by just having s bitmap and if a char repeats,
>>> any longer repeating substring will have those char repeated atleast twice,
>>> hence O(n) solution.
>>>
>>>
>>> Also, Hasaan: how is your algo O(n2) for for->while->for chain?
>>>
>>> Best Regards
>>> Ashish Goel
>>> "Think positive and find fuel in failure"
>>> +919985813081
>>> +919966006652
>>>
>>>
>>> On Tue, Jun 5, 2012 at 11:42 AM, Ashish Goel <ashg...@gmail.com> wrote:
>>>
>>>> Hassan, can you explain your algo?
>>>>
>>>> Best Regards
>>>> Ashish Goel
>>>> "Think positive and find fuel in failure"
>>>> +919985813081
>>>> +919966006652
>>>>
>>>>
>>>> On Mon, Jun 4, 2012 at 11:20 AM, Hassan Monfared 
>>>> <hmonfa...@gmail.com>wrote:
>>>>
>>>>> for
>>>>
>>>>
>>>>
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>
>
>
> --
> Regards
>
> Lomash Goyal
>
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