nope geke is valid string..

here is the link from where question was taken

http://geeksforgeeks.org/forum/topic/amazon-interview-question-password-checker

On Wed, Jun 6, 2012 at 11:44 AM, Ashish Goel <ashg...@gmail.com> wrote:

> Hassan geke should not be a valid string. The question states " which
> have the same substring following it " so here e follows e. There is no
> precondition that it has to follow immediate.
>
> Utsav: can you clarify?
>
>
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
>
> On Tue, Jun 5, 2012 at 11:32 PM, Hassan Monfared <hmonfa...@gmail.com>wrote:
>
>> yes It's valid, cuz  it doesn't have any repeated substring next together
>>
>>
>> On Tue, Jun 5, 2012 at 7:08 PM, Lomash Goyal <lomesh.go...@gmail.com>wrote:
>>
>>> is geke is a invalid strng?
>>>
>>>
>>> On Tue, Jun 5, 2012 at 12:17 PM, Hassan Monfared <hmonfa...@gmail.com>wrote:
>>>
>>>> Ashish:
>>>>
>>>> the algorithm passes over string and check if there is any substring
>>>> with len=1 is repeated or not. if not, tries for substring with len 2,...
>>>> and so on.
>>>> max length of substring which can be repeated can be at most  N/2.
>>>>
>>>>
>>>> Regards,
>>>>
>>>>
>>>> On Tue, Jun 5, 2012 at 10:48 AM, Ashish Goel <ashg...@gmail.com> wrote:
>>>>
>>>>> The problem suggests that a character can't be more than once present
>>>>> and thereby it can be done by just having s bitmap and if a char repeats,
>>>>> any longer repeating substring will have those char repeated atleast 
>>>>> twice,
>>>>> hence O(n) solution.
>>>>>
>>>>>
>>>>> Also, Hasaan: how is your algo O(n2) for for->while->for chain?
>>>>>
>>>>> Best Regards
>>>>> Ashish Goel
>>>>> "Think positive and find fuel in failure"
>>>>> +919985813081
>>>>> +919966006652
>>>>>
>>>>>
>>>>> On Tue, Jun 5, 2012 at 11:42 AM, Ashish Goel <ashg...@gmail.com>wrote:
>>>>>
>>>>>> Hassan, can you explain your algo?
>>>>>>
>>>>>> Best Regards
>>>>>> Ashish Goel
>>>>>> "Think positive and find fuel in failure"
>>>>>> +919985813081
>>>>>> +919966006652
>>>>>>
>>>>>>
>>>>>> On Mon, Jun 4, 2012 at 11:20 AM, Hassan Monfared <hmonfa...@gmail.com
>>>>>> > wrote:
>>>>>>
>>>>>>> for
>>>>>>
>>>>>>
>>>>>>
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>>>
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>>>
>>> *
>>> *
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