but i am confused in this problem...
int a=10;
int b;
b=--a--;
printf("%d %d",a,b);..what will output?

On Sun, Jul 8, 2012 at 11:39 PM, md shaukat ali <ali.mdshau...@gmail.com>wrote:

> agree with adarsh
>
>
> On Sun, Jul 8, 2012 at 10:39 PM, adarsh kumar <algog...@gmail.com> wrote:
>
>> Sorry, its 6/6 and not 6/5,
>>
>> regds.
>>
>> On Sun, Jul 8, 2012 at 10:39 PM, adarsh kumar <algog...@gmail.com> wrote:
>>
>>> Firstly, this is ambiguous and expressions with multiple
>>> increment/decrement operators will get executed according to the compiler.
>>>
>>> Even if you consider the normal way, as we(humans) percieve it, it will
>>> be evaluated as
>>> (++i)/(i++), which is 6/5, which is 1.
>>>
>>> Simple!
>>>
>>>
>>>
>>> On Sun, Jul 8, 2012 at 10:23 PM, rahul sharma 
>>> <rahul23111...@gmail.com>wrote:
>>>
>>>> int i=5;
>>>> i=++i/i++;
>>>> print i;
>>>>
>>>>
>>>> i=1
>>>>
>>>> how?
>>>>
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