i dont think it will work like u said...7/5....i think it will go as
6/6=1..explain nyone???

On Mon, Jul 9, 2012 at 6:38 PM, Firoz Khursheed <firozkhursh...@gmail.com>wrote:

> int i=5;
> i=++i/i++;
> print i;
>
>
> i=1
> coz ++ operator in c has preference from right to left, therefor  first
> (i++ is ca;cu;ated) i=5 is used then it's incremented ie i=6 now. Now at
> this point of time ++i is calculated, which makes i=7;
> finally / operator is performed and i=7/5 is calculated, which makes i=1.
>
> Similarly,
>  int b=a++*a--;
> can be calculated using the preference rule.
>
> On Mon, Jul 9, 2012 at 12:16 PM, rahul sharma <rahul23111...@gmail.com>wrote:
>
>> what about post increment??????
>>
>>
>> On Sun, Jul 8, 2012 at 10:37 PM, mitaksh gupta <mitak...@gmail.com>wrote:
>>
>>> the o/p will be 2 not 1 because of the post-increment operator.
>>>
>>> On Sun, Jul 8, 2012 at 10:23 PM, rahul sharma 
>>> <rahul23111...@gmail.com>wrote:
>>>
>>>> int i=5;
>>>> i=++i/i++;
>>>> print i;
>>>>
>>>>
>>>> i=1
>>>>
>>>> how?
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>
>
>
> --
> Firoz Khursheed
> Computer Science & Engineering
>
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