I think it should output:
9 9
On Sun, Jul 8, 2012 at 11:42 PM, md shaukat ali <ali.mdshau...@gmail.com>wrote:
> but i am confused in this problem...
> int a=10;
> int b;
> b=--a--;
> printf("%d %d",a,b);..what will output?
>
>
> On Sun, Jul 8, 2012 at 11:39 PM, md shaukat ali
> <ali.mdshau...@gmail.com>wrote:
>
>> agree with adarsh
>>
>>
>> On Sun, Jul 8, 2012 at 10:39 PM, adarsh kumar <algog...@gmail.com> wrote:
>>
>>> Sorry, its 6/6 and not 6/5,
>>>
>>> regds.
>>>
>>> On Sun, Jul 8, 2012 at 10:39 PM, adarsh kumar <algog...@gmail.com>wrote:
>>>
>>>> Firstly, this is ambiguous and expressions with multiple
>>>> increment/decrement operators will get executed according to the compiler.
>>>>
>>>> Even if you consider the normal way, as we(humans) percieve it, it will
>>>> be evaluated as
>>>> (++i)/(i++), which is 6/5, which is 1.
>>>>
>>>> Simple!
>>>>
>>>>
>>>>
>>>> On Sun, Jul 8, 2012 at 10:23 PM, rahul sharma
>>>> <rahul23111...@gmail.com>wrote:
>>>>
>>>>> int i=5;
>>>>> i=++i/i++;
>>>>> print i;
>>>>>
>>>>>
>>>>> i=1
>>>>>
>>>>> how?
>>>>>
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>>>>
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