On Jul 3, Paul said:
>> > foo => 'bar'
>> > 'foo' => 'bar'
>>
>> And are they the same as:
>>
>> "foo" => "bar"
>> 'foo' => "bar"
>
>Those aren't the same.
>"$foo" is very different from '$foo'....
>I think => does interpolative double-ish quoting, doesn't it?
=> does no interpolation. None is possible/required. A bareword is
matched by
/^[A-Za-z_]\w*/
So there's no interpolation needed.
NOTE: -foo is a NOT bareword. The unary - before that which WOULD be a
bareword makes it NOT a bareword.
NOTE 2: This is cool:
print -foo; # -foo
# print --foo; # SYNTAX ERROR
print +-foo; # -foo
print -+-foo; # +foo
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
I am Marillion, the wielder of Ringril, known as Hesinaur, the Winter-Sun.
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