Hi Tim,
just a note.
On Sun, 23 Jun 2013 09:39:48 +0100
timothy adigun <2teezp...@gmail.com> wrote:
> Hi lee,
> Please, check my comment below:
>
> On Sun, Jun 23, 2013 at 3:43 AM, lee <l...@yun.yagibdah.de> wrote:
>
> > James Alton <jamesalton...@gmail.com> writes:
> >
> > > lee,
> > >
> > > You have a post statement if and then a code block. You can only use one
> > of
> > > two forms:
> > >
> > > print "test" if $color eq "blue"; #no parenthesis required
> > > if($color eq "blue"){print "test";}
> >
> > ++
>
> > And I can't have 'last if $color eq "blue" print "test\n";'? That would
> > be something quite natural and a logical thing to do ...
> >
> > logical? How is that? Wrap up, the function 'print' and 'last' in the if
> statement like so:
> if( $color eq "blue"){
> print "test\n";
> last LABEL;
> }
> NOTE: That when last is used the loop in question is immediately exits
> and execution start at the LABEL statement if provided. So any code after
> the last function is not disregarded.
>
"last" is not a function (a.k.a "subroutine") - it cannot be. It is a special
statement which is handled in a special way by the Perl interpreter. "redo" and
"next" are not functions either for a similar reason.
Regards,
Shlomi Fish
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