Hi Shlomi,
On Sun, Jun 23, 2013 at 10:02 AM, Shlomi Fish <shlo...@shlomifish.org>wrote:
> Hi Tim,
>
> just a note.
>
> On Sun, 23 Jun 2013 09:39:48 +0100
> timothy adigun <2teezp...@gmail.com> wrote:
>
> > Hi lee,
> > Please, check my comment below:
> >
> > On Sun, Jun 23, 2013 at 3:43 AM, lee <l...@yun.yagibdah.de> wrote:
> >
> > > James Alton <jamesalton...@gmail.com> writes:
> > >
> > > > lee,
> > > >
> > > > You have a post statement if and then a code block. You can only use
> one
> > > of
> > > > two forms:
> > > >
> > > > print "test" if $color eq "blue"; #no parenthesis required
> > > > if($color eq "blue"){print "test";}
> > >
> > > ++
> >
> > > And I can't have 'last if $color eq "blue" print "test\n";'? That
> would
> > > be something quite natural and a logical thing to do ...
> > >
> > > logical? How is that? Wrap up, the function 'print' and 'last' in the
> if
> > statement like so:
> > if( $color eq "blue"){
> > print "test\n";
> > last LABEL;
> > }
> > NOTE: That when last is used the loop in question is immediately exits
> > and execution start at the LABEL statement if provided. So any code after
> > the last function is not disregarded.
> >
>
> "last" is not a function (a.k.a "subroutine") - it cannot be. It is a
> special
> statement which is handled in a special way by the Perl interpreter.
> "redo" and
> "next" are not functions either for a similar reason.
>
> ++. You are right. It's a keyword related to the control flow of Perl
program.
I mistook it for a function (a.k.a "subroutine") because I could use this
"perldoc -f last" from CLI.
Thanks for look out for me... :)
> Regards,
>
> Shlomi Fish
>
> --
> -----------------------------------------------------------------
> Shlomi Fish http://www.shlomifish.org/
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--
Tim
