Brandon McCaig wrote:
On Sun, Jun 23, 2013 at 12:02:38PM +0300, Shlomi Fish wrote:
"last" is not a function (a.k.a "subroutine") - it cannot be.
It is a special statement which is handled in a special way by
the Perl interpreter. "redo" and "next" are not functions
either for a similar reason.
I think we can all agree that last is not a function/subroutine,
but at the same time it does behave like one in several ways. :)
No, it doesn't.
For example, you can follow it with parenthesis if you want
(albeit, there's no good reason to do that).
#!/usr/bin/perl
use strict;
use warnings;
while(1) {
last();
}
The parentheses in this case do nothing, and they certainly don't imply
that last is a function.
$ perl -le'
use warnings;
use strict;
for (1..2) {
();
}
'
$
__END__
Similarly, you can even wrap it up in a subroutine and it still
works as intended (so obviously it understands just how to find
the right enclosing block even through subroutine calls).
#!/usr/bin/perl
use strict;
use warnings;
while(1) {
my_last;
}
sub my_last {
last;
}
That won't work:
$ perl -le'
use warnings;
use strict;
while () {
my_last;
}
sub my_last {
last;
}
'
Bareword "my_last" not allowed while "strict subs" in use at -e line 5.
Execution of -e aborted due to compilation errors.
And even if you fix that bareword you still get a warning:
$ perl -le'
use warnings;
use strict;
while () {
my_last();
}
sub my_last {
last;
}
'
Exiting subroutine via last at -e line 8.
John
--
Any intelligent fool can make things bigger and
more complex... It takes a touch of genius -
and a lot of courage to move in the opposite
direction. -- Albert Einstein
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