I have a string that looks like Operator Overview#PGM#Report about all configured operators#/opt/OV/bin/OpC/call_sqlplus.sh all_oper#
I want to replace the last "#" with a newline. I've come up with a few ideas like substr ($_, rindex ($_, "#"), 1) = "\n" ; or substr ($_, length ($_) - 1, 1) = "\n" ; or chop ; $_ .= "\n" ; Are there any better ways, maybe using s/// or tr/// ? TIA... -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
