if you want to use s/// you can say s/(.*)#/$1\n/; ----- Original Message ----- From: "Busse, Rich" <[EMAIL PROTECTED]> To: "Perl Beginners" <[EMAIL PROTECTED]> Sent: Tuesday, July 23, 2002 9:00 AM Subject: Replace last # with \n
> I have a string that looks like > > Operator Overview#PGM#Report about all configured > operators#/opt/OV/bin/OpC/call_sqlplus.sh all_oper# > > I want to replace the last "#" with a newline. I've come up with a few ideas > like > > substr ($_, rindex ($_, "#"), 1) = "\n" ; > or > substr ($_, length ($_) - 1, 1) = "\n" ; > or > chop ; $_ .= "\n" ; > > Are there any better ways, maybe using s/// or tr/// ? TIA... > > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
