Frank Wiles wrote at Wed, 12 Mar 2003 10:14:16 -0600: > If you're wanting to find the last digit in a scalar, you'll want to > modify this to be: > > ($match) = $num =~ /(\d)$/; > > or if there is always there characters you can also do this: > > ($match) = $num =~ /\d\d(\d)/;
or my $last_digit = substr $num, -1; Greetings, Janek -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
