Thanks Peter!,
PS> That's because you missed out the next line, where the value from
PS> (the equivalent of) @$valref{cn} is dereferenced again with
PS> @$attrVal.
PS> I don't know why the dereferencing is done in the example with
PS> @$valref{$attrName}; that's needlessly complicated (single element slice
PS> of hash via reference?!). It'd make more sense to use -> :
PS> print $valref->{cn}->[0];
PS> (Assuming you have only one cn, as most people do.)
PS> In fact, you can get it right from the search result.
PS> $result->as_struct returns a reference to a hash keyed by DN, with values being
PS> references to hashes keyed by attribute name, whose values are references to
PS> arrays of attribute values. So:
PS> my $href = $result->as_struct;
PS> for my $dn (keys %$href) {
PS> print "cn of $dn is $href->{$dn}{cn}[0]\n";
PS> }
That is exactly what I was looking for!
PS> (That's taking advantage of the fact that you can leave out -> between
PS> closing and opening {} or [].)
So my problem was that I was dereferencing the hash, but not the array
reference it was talking About? or was it that I was not using the [0]?
--
Tim Musson
Flying with The Bat! eMail v1.62q
Windows 2000 5.0.2195 (Service Pack 2)
The generation of random numbers is too important to be left to chance.
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