Help me to understand your explanation of "assigning a hash reference to a hash."
Considering
my %params = { protocol => 2, interactive => 1, identity_files => [EMAIL PROTECTED], };
It appears to have an even number of elements like a hash should (since "=>" works essentially like ",") but the right hand side should be delimited by () instead of {} for it to be properly assigned as the value of a hash. With {} the right hand side is really a hash reference and has its location as its value which accounts for the error message "Reference found where even-sized list expected"???
This sounds correct so I am not sure what the question is. Essentially you have to think of the assignment of,
%params =
Such that the right side is taken in list context, rather than any specific type of value. So if you have a single value on the right then it gets set as a key without a corresponding value because that is how it is seen in list context, so when that value is a set of braces,
%params = {};
Then it is a single value in list context (and the reference is stringified to boot), where that value is seen as a hash reference by definition. Where as the parenthesis just reinforce list context on the right side and allow multiple values in a key/value, key/value, key/value... fashion to be assigned to the hash elements.
%params = ( 'key' => 'value', 'key' => 'value' );
So you have two ways to write your code, either the more common:
%params = ( 'protocol' => 2, 'interactive' => 1, 'identity_files' => [EMAIL PROTECTED], );
Or using a hash reference (note assignment is to a scalar):
$params = { 'protocol' => 2, 'interactive' => 1, 'identity_files' => [EMAIL PROTECTED], };
And then when using the variable you would do so such as:
Net::SSH::Perl->new($host, %params);
or,
Net::SSH::Perl->new($host, %$params);
perldoc perlreftut perldoc perlref
For more on references....
Does this clear things up or muddy the water further?
http://danconia.org
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