> Howdy list.
> I'm trying to one lineify this:
>
> my $guts = $firstchoice || '';
> if(!$guts && $use_second_choice_if_first_is_empty) {
> $guts = $secondchoice;
> }
>
> Basically
> my $guts = $firstchoice || $secondchoic || '';
> Would be perfect except I only want to let it use $seconchoice if
$use_second_choice_if_first_is_empty has a true value.
> This does not work like I want but illustrates the goal if you read it
our loud.
> my $guts = $firstchoice || $secondchoic if
$use_second_choice_if_first_is_empty || '';
>
> Is that possible to do with one line?
>
> TIA
>
> Dan
Seems like the ternary operator should set you up... perldoc perlop look
for "Conditional Operator"...
my $guts = (($firstchoice ne '') ? $firstchoice : (($firstchoice eq '')
? $secondchoice : ''));
Though there may be a better way using some combination of ||= or am I
misunderstanding you completely?
http://danconia.org
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