Hi everyone,
I use a form to upload files and currently i do this with jquery to
simulate ajax, so if I want to pass the file data to my jquery
function I do this:
<div class="submit"><button onClick="refreshattachments(this.form)"
type="button">Upload</button></div>
But I want to switch to AJAX and I dont know how to pass the form data
within an ajax link:
echo $form->create('Links',
array('name'=>'uploadAttachmentsForm','id'=>'uploadAttachmentsForm','type'=>'file'));
echo $form->file('Links');
echo $ajax->link('Upload', '/links/processattachment'.this.form,
array('update' => 'attachments_content')
);
echo $form->end();
aware that "$ajax->link('Upload', '/links/
processattachment'.this.form," is far away from right I stil gave it a
shot.
Can someone help me? Thank you. I appreciate it.
Check out the new CakePHP Questions site http://cakeqs.org and help others with
their CakePHP related questions.
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at
http://groups.google.com/group/cake-php?hl=en
