How would you go about this?
Kim
Sent from my iPhone
On 08/06/2009, at 21.35, "Rob" <[email protected]> wrote:
Kim,
One thing that has helped me understand it is to do it in reverse.
Instead
of getting say 64 address and trying to convert them to one or more,
I start
with an answer I want and work my way backwards.
I always start with the Binary answer when I do some of these
problems.
Once I could work them from both directions it made it easy to
understand
them.
Rob
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Kim Pedersen
Sent: Monday, June 08, 2009 2:04 PM
To: Joe Astorino
Cc: [email protected]
Subject: Re: [OSL | CCIE_RS] ACL Wildcards
Will do :)
Im assuming its one of the things you go through in the Bootcamps as
well?
Kim
Joe Astorino wrote:
If you have any specific issues let us know, we'll do our best to
make it
as
clear as possible for you!
Regards,
Joe Astorino
CCIE #24347 (R&S)
Sr. Support Engineer - IPexpert, Inc.
URL: http://www.IPexpert.com
-----Original Message-----
From: Kim Pedersen [mailto:[email protected]]
Sent: Monday, June 08, 2009 2:52 PM
To: Joe Astorino
Cc: 'Tyson Scott'; [email protected]
Subject: Re: [OSL | CCIE_RS] ACL Wildcards
Hi,
Okay, hope when i hit the workbooks something gets clearer on what
exactly
to go through :)
Sincerely,
Kim
Joe Astorino wrote:
Yeah, you are right there is no "absolute" way like most things in
this business. 2 lines is just an easy example to show the idea...I
agree it becomes much more confusing with more. Writing things out
always helps me to see the big picture clearer. When you write a
line
for an ACL think through in your head "OK what EXACT range of
addresses does this permit/deny"
Regards,
Joe Astorino
CCIE #24347 (R&S)
Sr. Support Engineer - IPexpert, Inc.
URL: http://www.IPexpert.com
-----Original Message-----
From: Kim Pedersen [mailto:[email protected]]
Sent: Monday, June 08, 2009 2:46 PM
To: Joe Astorino
Cc: 'Tyson Scott'; [email protected]
Subject: Re: [OSL | CCIE_RS] ACL Wildcards
Hi Joe,
Yeah, i can see that working with 2 lines, but how about more? :)
and the VOD said it was not an absolute way...
Phew.. confusing.
Sincerely,
Kim
Joe Astorino wrote:
Once you do enough of them, you will find your own patterns and
ways,
but if you use simple subtraction and look for the difference to
be a
power of 2 that really helps! For instance in the first octet if
you
have say 192 and 200 ... 200 - 192 = 8 = 2^3 ...so you know you can
match them both with 1 bit in the "8" place.
Regards,
Joe Astorino
CCIE #24347 (R&S)
Sr. Support Engineer - IPexpert, Inc.
URL: http://www.IPexpert.com
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Kim
Pedersen
Sent: Monday, June 08, 2009 2:27 PM
To: Tyson Scott
Cc: [email protected]
Subject: Re: [OSL | CCIE_RS] ACL Wildcards
Thanks for all of your help...
When you guys do it, do you start by writing it all out in binary,
or make an educated guess on what groups together? and it is best
to
start with the first octet and going forward, or the last going
backwards?
Again, Thanks!
Sincerely,
Kim Pedersen
Tyson Scott wrote:
Yes Correct Kim,
194 and 193 can defiantly be matched in one line if all the rest
were the same. In your example none of those could be combined
into
one line without matching additional networks.
Regards,
Tyson Scott - CCIE #13513 R&S and Security Technical Instructor -
IPexpert, Inc.
Telephone: +1.810.326.1444
Cell: +1.248.504.7309
Fax: +1.810.454.0130
Mailto: [email protected]
Join our free online support and peer group communities:
http://www.IPexpert.com/communities
IPexpert - The Global Leader in Self-Study, Classroom-Based, Video
On Demand and Audio Certification Training Tools for the Cisco
CCIE
R&S Lab, CCIE Security Lab, CCIE Service Provider Lab , CCIE Voice
Lab and CCIE Storage Lab Certifications.
-----Original Message-----
From: Kim Pedersen [mailto:[email protected]]
Sent: Monday, June 08, 2009 2:02 PM
To: Tyson Scott
Cc: 'Bryan Bartik'; [email protected]
Subject: Re: [OSL | CCIE_RS] ACL Wildcards
Hi Tyson,
In my example, those 4 bits are just in the first octet alone. So
im assuming we really need to treat the entire address, and not
just
by
octet?
So there's no "set-in-stone" rules to go by, you just sort of
have
to group them, see if that matches and go from there?
Finally, in my example, if i add the 193 prefix, I would have 6
bits of difference, so the closest i could do in one line is by
matching 64 nets, and this would give an indication on whether i
need to narrow it
down?
Sincerely,
Kim
Tyson Scott wrote:
Kim
When it has a large amount of differences you need to find
similarities between them to put them together
194 is 11000010
174 is 10101110
This is 4 bit differences so you would have to have 16 entries to
match
them
as one line without matching additional subnets
It is important to also note if they say to not match any
additional networks or if they just say to combine them to as few
lines without specifying that you can't match additional
networks as
well.
Regards,
Tyson Scott - CCIE #13513 R&S and Security Technical Instructor -
IPexpert, Inc.
Telephone: +1.810.326.1444
Cell: +1.248.504.7309
Fax: +1.810.454.0130
Mailto: [email protected]
Join our free online support and peer group communities:
http://www.IPexpert.com/communities
IPexpert - The Global Leader in Self-Study, Classroom-Based,
Video
On
Demand
and Audio Certification Training Tools for the Cisco CCIE R&S
Lab,
CCIE Security Lab, CCIE Service Provider Lab , CCIE Voice Lab and
CCIE Storage Lab Certifications.
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Kim
Pedersen
Sent: Monday, June 08, 2009 11:28 AM
To: Bryan Bartik
Cc: [email protected]
Subject: Re: [OSL | CCIE_RS] ACL Wildcards
Hi Bryan,
I guess I didnt point out the problem (sounds soo serious :) ),
but what if the question states: "make these into as few
entries as
possible", and they are soo different that it might not end up in
one entry (again, with difference in multiple octets).
For example (no logic behind choosing these):
194.64.0.96/27
174.34.87.64/26
193.23.10.8/30
...
Next, imagine 32 addresses just like this :)
How do you go about breaking all of this down?
Sincerely,
Kim Pedersen
Bryan Bartik wrote:
Kim, even if there is more than one octet you still can look at
the number of bits that are different. Example:
192.168.0.0
192.168.0.1
192.168.1.0
192.168.1.1
The above addresses have 2 bits (bit 0 in the 3rd and 4th
octets)
that differ and we can combine them in one ACL.
3rd and 4th octets:
0000 0000 | 0000 0000
0000 0000 | 0000 0001
0000 0001 | 0000 0000
0000 0001 | 0000 0001
0000 0000 | 0000 0000 AND
0000 0001 | 0000 0001 XOR
192.168.0.0 0.0.1.1 would be the ACL entry.
-hth
Bryan Bartik
CCIE #23707 (R&S), CCNP
Sr. Support Engineer - IPexpert, Inc.
URL: http://www.IPexpert.com
On Mon, Jun 8, 2009 at 7:47 AM, Rodriguez, Jorge
<[email protected]
<mailto:[email protected]>> wrote:
Jeremy this should help you in doing the calculating
wildcard
mask
http://www.internetworkexpert.com/resources/01700370.htm
http://blog.internetworkexpert.com/2007/12/26/q-how-do-i-compute-com
p
l
ex-wil
dcard-masks-for-access-lists/
Rgds
Jorge
*From:* [email protected]
<mailto:[email protected]>
[mailto:[email protected]
<mailto:[email protected]>] *On Behalf Of
*JEREMY FURR (RIT Student)
*Sent:* Friday, June 05, 2009 10:12 AM
*To:* [email protected]
<mailto:[email protected]>
*Subject:* [OSL | CCIE_RS] ACL Wildcards
Does anyone know of a website or book that explains well
how ACL
wildcards work? I have been trying to filter out four
blocks from
a bunch of route advertisments but just can't get the three I
want
through, this is what I have R2 is originating 192.168.2.0/24
<http://192.168.2.0/24> through 192.168.15.0/24
<http://192.168.15.0/24> in RIP to R1. I want to only accept
blocks 192.168.5.0, 192.168.10.0, 192.168.13.0 and
192.168.14.0
If I use acl with 192.168.10.0 0.0.4.0, I will get 10 and
14 but
not thirteen. For the 5 network I just use the 192.168.5.0
0.0.0.255.
Any thoughts or help would be appreciated.
Jeremy Furr
[email protected] <mailto:[email protected]>
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