Hi Derek

The symmetry of the self-RF is explained in detail in the documentation for 
POLARRFN, in fact I would advise you to use this because you can then plot 
monoclinic space groups with the unique b axis along the orthogonal Z axis 
(NCODE = 3) and then the symmetry is *much* easier to interpret.  Also POLARRFN 
allows you to plot all the kappa sections not just 4 selected ones.  This can 
be important if the NCS 2-fold is not exact, i.e. you may see the peaks 
slightly displaced off the kappa=180 or other point-group sections (60, 90, 
120).  To do the same with MOLREP requires ~ 70 jobs!  Note you may need high 
resolution data (say 2 Ang or better) for this and also sharpening using ECALC 
so that the peaks are resolved.

According to polarrfn.doc the symmetry generated by a 2-fold along b parallel 
to Z is (180-theta, 180-phi, kappa) so the peak in the list (159,180,180) is 
the same as (21,0,180) which is a NCS 2-fold that you can see just below 
centre.  The peak (111,0,180) is thus the same as (69,180,180) near the top 
which is another NCS 2-fold perp to the first generated by the crystallographic 
2-fold.

HTH!

-- Ian

> -----Original Message-----
> From: [EMAIL PROTECTED] 
> [mailto:[EMAIL PROTECTED] On Behalf Of Derek Logan
> Sent: 23 April 2008 13:40
> To: CCP4BB@JISCMAIL.AC.UK
> Subject: Help with pseudosymmetry problem
> 
> Hi everyone,
> 
> Can anyone help me with interpretation of a self rotation 
> function and  
> native Patterson from a dataset with pseudosymmetry? I've 
> always been  
> a bit poor on spherical polars. The space group is P21 with beta =  
> 92.2°. The kappa=180° section of the SRF, calculated using 
> Molrep, is at
> 
> http://mole.mbfys.lu.se/~derek/selfRF_180.png
> 
> and contains two big peaks around 7 sigma. I'm having trouble  
> identifying these in the list of peaks from Molrep:
> 
>              theta    phi     chi    alpha    beta   gamma      
> Isym_i    Isym_j
> Sol_RF   1      0.00    0.00    0.00      0.00    0.00    0.00   1   1
> Sol_RF   1     90.00  -90.00  180.00      0.00  180.00    0.00   1   2
> Sol_RF   1     90.00   90.00  180.00      0.00  180.00    0.00   2   1
> Sol_RF   1      0.00    0.00    0.00      0.00    0.00    0.00   2   2
> Sol_RF   2    158.56  180.00  180.00      0.00   42.89 -180.00   1   1
> Sol_RF   2    111.44    0.00  180.00   -180.00  137.11    0.00   1   2
> Sol_RF   2    111.44    0.00  180.00    180.00  137.11    0.00   2   1
> Sol_RF   2     21.44    0.00  180.00    180.00  -42.89    0.00   2   2
> Sol_RF   3    165.65    0.00  180.00   -180.00   28.70    0.00   1   1
> Sol_RF   3    104.35 -180.00  180.00      0.00  151.30  180.00   1   2
> Sol_RF   3    104.35  180.00  180.00      0.00  151.30 -180.00   2   1
> Sol_RF   3     14.35 -180.00  180.00      0.00  -28.70  180.00   2   2
> 
> It seems to me to be two copies of peak 2. I believe theta starts in  
> the middle, perpendicular to the page and phi starts on the x axis,  
> thus the peak just below the centre would be (21.44, 0, 180). I  
> presume that the second peak is the symmetry-related (158.56, 
> 180, 0)?  
> However where is (111.44 0 180)? I would expect to see this near the  
> bottom of the plot, but it's not there. I'm sure I'm missing 
> something  
> fundamental about the symmetry of the SRF projection, but  
> unfortunately I don't have a supervisor to bug about this (I 
> *am* the  
> supervisor...)
> 
> In the native Patterson
> 
> http://mole.mbfys.lu.se/~derek/nativePatterson.png
> 
> there are two peaks of almost equal height. How can this be 
> reconciled  
> with having only one strong peak in the SRF? There are most 
> likely two  
> dimers in the asymmetric unit, but there may only be one, with very  
> high resulting solvent content. What's more the molecules are 
> leucine- 
> rich repeat proteins and have weak internal symmetry. I believe this  
> was an issue with the ribonuclease inhibitor, but looking briefly at  
> the crystallisation article and structure article I wasn't able to  
> find a rationalisation of this problem. The 2-fold is 
> perpendicular to  
> b*. How could this cause the two peaks?
> 
> Thanks
> Derek
> 
> 


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