Oscar
Has
A
Hunk
Of
Apples

Sin(theta) = Opposite/Hypotenuse => Sin(A) = x/z
Cos(theta) = Adjacent/Hypotenuse => Cos(A) = y/z
Tan(theta) = Opposite/Adjacent => Tan(A) = x/y

A = Atan(x/y) = Acos(y/z) = Asin(x/z)



-----Original Message-----
From: Haggerty, Mike [mailto:[EMAIL PROTECTED]]
Sent: Monday, December 30, 2002 3:03 PM
To: CF-Community
Subject: Geometry Question


I didn't pay attention in junior high and now have a question about
geometry. Anyone on the list know the answer?

I have a right triangle and know the size of the legs (and thus the size of
the hypotenuse). Now I want to calculate the size of the angles other than
the right one, and to write a simple formula to do this.

Anyone know how? I realize the size of both of the angles is equal to 90
degrees, and that the size of the angles is directly proportional to the
size of the legs at which they point. 

An expression of this would be:

For triangle ABC with hypotenuse z, where B is a right angle, where BC = x
and AB = y, A = ???




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