You want the ArcSine of the Opposite side divided by the Hypotenuse side.

And what are these radian things you talkin' 'bout? Ignore them. They were just a 
rumor. Like the metric system.

So, Angle=Arcsine(oppositeSide/Hypotenuse)

Now back to those pesky radians.

Cold fusion ASin function returns radians

In your example below...

<cfset AngleInDegrees=aSin(x/z)*(180/pi())>

Does this make any more sense?

Jerry Johnson


>>> [EMAIL PROTECTED] 12/30/02 03:34PM >>>
Oh dear, I must be a little worse off than I thought.

Taking a look at what you wrote has yielded little to me. I think I may be
confused over units, and perhaps converting radians to degrees improperly.

Would you mind stepping me through your formulas?

Say if, in triangle ABC, where B is a right angle and z is the hypotenuse,
when BC is x and AB is y, we have a value of 5 for y and 10 for x.

How do I apply these calculations to determine the angle of A in degrees?

Thanks,
M

-----Original Message-----
From: Lon Lentz [mailto:[EMAIL PROTECTED]] 
Sent: Monday, December 30, 2002 3:33 PM
To: CF-Community
Subject: RE: Geometry Question


Oscar
Has
A
Hunk
Of
Apples

Sin(theta) = Opposite/Hypotenuse => Sin(A) = x/z
Cos(theta) = Adjacent/Hypotenuse => Cos(A) = y/z
Tan(theta) = Opposite/Adjacent => Tan(A) = x/y

A = Atan(x/y) = Acos(y/z) = Asin(x/z)



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