Additionally(take that Ben) if you cant figure out the answer, sometimes,
you can prove that there is no answer!

-----Original Message-----
From: Candace Cottrell [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, December 31, 2002 7:22 AM
To: CF-Community
Subject: RE: Geometry Question


I guess I can't forget what I never took. I only went to Algebra 2 and
then I was on to better things, like an extra PE period and
photojournalism.  Oh yeah, and I ended up being a sophomore in college
my senior year in high school because I took college courses at the
local magnet center.
 
Math frightens me, but I do like the fact that there is ALWAYS a right
answer.
 
 
 
 
Candace K. Cottrell, Web Developer 
The Children's Medical Center 
One Children's Plaza 
Dayton, OH 45404 
937-641-4293 
http://www.childrensdayton.org
 
 
[EMAIL PROTECTED]

>>> [EMAIL PROTECTED] 12/30/2002 4:35:48 PM >>>
I've got a tangent cheat table sewed into my climbing pack, a compass,
and a 100 ft string marked at 10 ft increments.

I use the table to figure out how tall things are.

height of object = tan(angle) * distance from object

I always amaze people who forgot all their high school trig.

Jerry Johnson

>>> [EMAIL PROTECTED] 12/30/02 04:14PM >>>
You guys are scaring me....



Candace K. Cottrell, Web Developer 
The Children's Medical Center 
One Children's Plaza 
Dayton, OH 45404 
937-641-4293 
http://www.childrensdayton.org 


[EMAIL PROTECTED] 

>>> [EMAIL PROTECTED] 12/30/2002 4:00:04 PM >>>
Whether the calculation comes out in degrees or radians will depend on
the
arcsine/arccosine/arctangent functions used.  In CF, it's returned in
radians (as it should be!).

To convert radians to degrees, simply multiply by 180/pi.

So, in your example, the angle A in degrees would be
180/pi*arcsin(x/z)
or
180/pi*arccos(y/z)
or
180/pi*arctan(x/y)
which (should) all come out to be about
63.4 degrees.

did that help?



  --Ben Doom
    Programmer & General Lackey
    Moonbow Software

: -----Original Message-----
: From: Haggerty, Mike [mailto:[EMAIL PROTECTED]] 
: Sent: Monday, December 30, 2002 3:35 PM
: To: CF-Community
: Subject: RE: Geometry Question
:
:
: Oh dear, I must be a little worse off than I thought.
:
: Taking a look at what you wrote has yielded little to me. I think I
may be
: confused over units, and perhaps converting radians to degrees
improperly.
:
: Would you mind stepping me through your formulas?
:
: Say if, in triangle ABC, where B is a right angle and z is the
hypotenuse,
: when BC is x and AB is y, we have a value of 5 for y and 10 for x.
:
: How do I apply these calculations to determine the angle of A in
degrees?
:
: Thanks,
: M
:
: -----Original Message-----
: From: Lon Lentz [mailto:[EMAIL PROTECTED]] 
: Sent: Monday, December 30, 2002 3:33 PM
: To: CF-Community
: Subject: RE: Geometry Question
:
:
: Oscar
: Has
: A
: Hunk
: Of
: Apples
:
: Sin(theta) = Opposite/Hypotenuse => Sin(A) = x/z
: Cos(theta) = Adjacent/Hypotenuse => Cos(A) = y/z
: Tan(theta) = Opposite/Adjacent => Tan(A) = x/y
:
: A = Atan(x/y) = Acos(y/z) = Asin(x/z)
:
:
: 




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