Set value is a call to SetX() function, neither the argument of the SetX(), nor the result of the GetX(). So, expression a.x=5 always emits the following code as a result a.Setx(5). MSPropertyRefBuilder::buildSet() does not capture results at all. It just ignores
captureSetValueAsResult value. That's why we have to capture final result after 'set' is built completely. Best regards, Alexey Bataev ============= Software Engineer Intel Compiler Team 07.12.2015 11:07, John McCall пишет: > rjmccall added a comment. > > I don't understand why that's true. buildSet is called with > captureSetValueAsResult=true, and the set value is definitely capturable, so > that value should be set as the result; and you're not overriding it. Why > does the expression end up having type void? > > > http://reviews.llvm.org/D15174 > > > _______________________________________________ cfe-commits mailing list cfe-commits@lists.llvm.org http://lists.llvm.org/cgi-bin/mailman/listinfo/cfe-commits
