Can you show a code snippet on what your are doing? Maybe the screenshot you
are having is flash content (which it doesn't currently support)?  Maybe the
tab is invalid.

-Mohamed Mansour


On Sat, Dec 12, 2009 at 4:20 PM, Tom <tom.extensi...@googlemail.com> wrote:

> Thanks Mohamed,
>
> It all seems to be working, how ever the images are appearing blank.
> They are 1440x780 and in inspector there are no errors reported. Even
> when capturing the current window the images appear blank.
>
> Tom
>
> On Dec 12, 8:52 pm, Mohamed Mansour <m...@chromium.org> wrote:
> > Hi Tom,
> >
> > You are placing the wrong thing in the source attribute:
> http://code.google.com/chrome/extensions/tabs.html#method-captureVisi...
> >
> > <http://code.google.com/chrome/extensions/tabs.html#method-captureVisi..
> .>The
> > callback function for captureVisibleTab has this defined as:
> > "function(string dataUrl) {...})"
> >
> >  You would use the "dataUrl" to assign the 'src' property of an HTML
> Image
> > element for display.
> >
> > An example being:
> >
> > <script>
> > chrome.tabs.captureVisibleTab(null, function(dataUrl) {
> >   content = document.getElementById('screenshots');
> >   var image = document.createElement('img');
> >   image.setAttribute('src', dataUrl);
> >   content.appendChild(image);});
> >
> > </script>
> >
> > <span id="screenshots"></span>
> >
> > -Mohamed Mansour
> >
> >
> >
> > On Sat, Dec 12, 2009 at 11:55 AM, Tom <tom.extensi...@googlemail.com>
> wrote:
> > > Is it supposed to be used like this?
> >
> > > var visualTab = chrome.tabs.captureVisibleTab(20, function(capture)
> > > {}););
> > > document.getElementById('content').innerHTML += '<img src="'+visualTab
> > > +'" />';
> >
> > > Thats what I'm doing at the moment and I can't get it to work. (I'm
> > > sure 20 is a valid tab id)
> >
> > > Please could someone tell me what I'm doing wrong.
> >
> > > Thanks
> >
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